JavaScript Code Daily Challenge #10
Lakshya Tyagi

Lakshya Tyagi @lakshyatyagi24

Location:
Greater noida, India
Joined:
Sep 1, 2020

JavaScript Code Daily Challenge #10

Publish Date: Dec 1 '20
7 1

About

This is a series of JavaScript Code Daily Challenge. Each day I show a few solutions written in JavaScript. The questions are from coding practice/contest sites such as HackerRank, LeetCode, Codeforces, Atcoder and etc.

Number Line Jumps
https://www.hackerrank.com/challenges/kangaroo

'use strict';

const fs = require('fs');

process.stdin.resume();
process.stdin.setEncoding('utf-8');

let inputString = '';
let currentLine = 0;

process.stdin.on('data', inputStdin => {
    inputString += inputStdin;
});

process.stdin.on('end', _ => {
    inputString = inputString.replace(/\s*$/, '')
        .split('\n')
        .map(str => str.replace(/\s*$/, ''));

    main();
});

function readLine() {
    return inputString[currentLine++];
}
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Complete the kangaroo function in comment.

function kangaroo(x1, v1, x2, v2) {

}
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function main() {
    const ws = fs.createWriteStream(process.env.OUTPUT_PATH);

    const x1V1X2V2 = readLine().split(' ');

    const x1 = parseInt(x1V1X2V2[0], 10);

    const v1 = parseInt(x1V1X2V2[1], 10);

    const x2 = parseInt(x1V1X2V2[2], 10);

    const v2 = parseInt(x1V1X2V2[3], 10);

    let result = kangaroo(x1, v1, x2, v2);

    ws.write(result + "\n");

    ws.end();
}
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Comments 1 total

  • Lakshya Tyagi
    Lakshya TyagiDec 2, 2020
    function kangaroo(x1, v1, x2, v2) {
      let n = 0;
      while (n < 10000) {
        if (x1 + n * v1 === x2 + n * v2) {
          return "YES";
        }
        n++;
      }
      return "NO";
    }
    
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