Introduction

Here we are given an array, now we have to traverse the array and check for every index element , how many numbers are smaller than it. And we have to count it and store it in a new array. Like nums = [8,1,2,2,3] , Output: [4,0,1,1,3].

Examples

Steps

1. take new array and counter variable
2. run a nested for loop.
3. Both starts from 0 and ends in nums.length
4. if( i == j), then skip
5. else if( nums[i] > nums[j]) , count++;
6. arr[i] = count;
7. return arr;

Hints

JavaCode

class Solution {
    public int[] smallerNumbersThanCurrent(int[] nums) {
        int arr[] = new int[nums.length];
        for(int i = 0; i<nums.length; i++){
            int count = 0;
            for(int j=0; j< nums.length; j++){
                if ( i == j){
                    continue;
                }
                else if(nums[i] > nums[j]){
                    count++;
                }
            }
            arr[i] = count;
        }
        return arr;
    }
}

Output